Free web host – 3.3.4 ANSWERS TO EXERCISES 543 3. a2 E

Posted on March 22, 2008 Posted in Uncategorized

3.3.4 ANSWERS TO EXERCISES 543 3. a2 E 2a -1 and a3 = 3a -2 (modulo m). By considering all short solutions of (15), we find that V: = 6 and V: = 4, for the respective vectors (1, -2,1) and (1, -1, -1, l), except in the following cases: …

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